Type the Question

Saturday, February 16, 2019

Question Name:MIN MAX

#include <stdio.h>
int main()
{
int a,b[10],i,max=0,min=100;
  
  scanf("%d",&a);
  for(i=0;i<a;i++) 
  { 
    scanf("%d",&b[i]);
  } 
    for(i=0;i<a;i++) 
    { 
      if(min>b[i]) { min=b[i];} 
            if(max<b[i]) { max=b[i];} 
    } 
  printf("Minimum element in an array : %d\n",min);
  printf("Maximum element in an array : %d",max);
 return 0;
}
  • Problem Description
    Given a list of N integers, your task is to find out the miniumum and maximum.

    Input Format:

    No.of integers and the integers
  • Test Case 1
    Input (stdin) 5
    2 3 1 6 7
    Expected OutputMinimum element in an array : 1
    Maximum element in an array : 7
  • Test Case 2
    Input (stdin)6
    11 2 10 6 5 1
    Expected OutputMinimum element in an array : 1
    Maximum element in an array : 11

1 comment:

  1. #include
    #include
    using namespace std;


    int main()
    {

    int n;
    cin>>n;
    int k;
    cin>>k;
    int arr[n];

    for(int i =0;i>arr[i];

    int unfairness = INT_MAX;
    sort(arr,arr+n);
    for (int i = 0; i < n - k + 1; i++){
    if (arr[i+k-1]-arr[i]<unfairness)
    unfairness = arr[i+k-1]-arr[i];
    }

    cout<<unfairness;

    return 0;
    }

    ReplyDelete

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