#include <stdio.h>
#include<string.h>
int main()
{
char name[10][20];
long num[10];
int count=0,i;
for(i=0;i<10;i++)
{
scanf("%s",&name[i][20]);
scanf("%lu",&num[i]);
if(num[i]==103101)
count++;
}
if(count)
printf("Student register number 103101 is exist");
else
printf("Student register number 103101 is not exist");
return 0;
}
Problem Description
HoD
have to find the name having registration number 103101 in the final
year name list. Names will be in alphabetical order, HoD have to check
each and every name in the name list to identify the particular
registration number.
Test Case 1
Input (stdin)
Thomas 101010
Imran 101015
Sithik 101025
Setan 101024
Milton 101045
Arjun 101084
Rakesh 103101
Hrithik 101036
Ayush 101052
Aswathy 101087
Expected Output
Student register number 103101 is exist
Test Case 2
Input (stdin)
Kavi 101010
Imran 101015
Chandu 101025
Navin 101024
Milton 101045
Arjun 101084
Mukil 1010023
Hrithik 101036
Ayush 101052
Aswathy 101087
Expected Output
Student register number 103101 is not exist
can someone send the answer in c++
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